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1
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#include <stdio.h>
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2
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#include <time.h>
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3
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#include <termios.h>
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4
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#include <errno.h>
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5
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#include <fcntl.h>
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6
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#include <QList>
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7
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8
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9
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10
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float E12[]
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11
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{
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12
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100, 120, 150, 180, 220, 270, 330, 390, 470, 560, 680, 820,
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13
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1000, 1200, 1500, 1800, 2200, 2700, 3300, 3900, 4700, 5600, 6800, 8200,
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14
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10000, 12000, 15000, 18000, 22000, 27000, 33000, 39000, 47000, 56000, 68000, 82000,
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15
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};
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16
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17
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float E24[]
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{
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19
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100, 110, 120, 130, 150, 160, 180, 200, 220, 240, 270, 300, 330, 360, 390, 430, 470, 510, 560, 620, 680, 750, 820, 910,
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20
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1000, 1100, 1200, 1300, 1500, 1600, 1800, 2000, 2200, 2400, 2700, 3000, 3300, 3600, 3900, 4300, 4700, 5100, 5600, 6200, 6800, 7500, 8200, 9100,
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21
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10000, 11000, 12000, 13000, 15000, 16000, 18000, 20000, 22000, 24000, 27000, 30000, 33000, 36000, 39000, 43000, 47000, 51000, 56000, 62000, 68000, 75000, 82000, 91000
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22
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};
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23
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24
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#define E E12
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26
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27
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28
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29
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float voltage_U2( float u, float r1, float r2 )
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30
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{
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return( ( u * r2 ) / ( r1 + r2 ) );
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32
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};
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33
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34
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35
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float r_ges(float r1, float r2)
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36
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{
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37
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// https://studyflix.de/elektrotechnik/parallelschaltung-widerstand-4533
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38
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return( ( r1 * r2 ) / ( r1 + r2 ) );
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39
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}
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40
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41
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42
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int main()
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{
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44
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float total=36.0;
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45
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float target=0.045;
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46
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int bestR1=-1;
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47
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int bestR2=-1;
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48
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int bestR3=-1;
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49
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float bestVoltage=1000000;
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50
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float v;
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51
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52
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int count=sizeof(E)/sizeof(E[0]);
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53
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54
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//printf("%g Ohm\n", r2(target, 1000.0) );
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55
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for(int i1=0; i1<count; i1++)
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56
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{
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// if( ( E[i1] >= 1000 ) && ( E[i1] <= 5000 ) )
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//if( E[i1] == 1000 )
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59
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{
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60
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for(int i2=0; i2<count; i2++)
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61
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{
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62
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//for(int i3=0; i3<count; i3++)
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63
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{
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64
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v=voltage_U2( total, E[i1], E[i2] );
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65
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printf("%g V\n", v );
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66
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if( ( v >= target ) && ( v < bestVoltage ) )
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67
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{
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68
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bestR1=i1;
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69
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bestR2=i2;
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70
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bestVoltage=v;
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71
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}
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72
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}
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73
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}
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74
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}
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75
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}
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76
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printf("%d/%d\n", bestR1, bestR2, bestR3 );
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printf("R1=%g\n", E[bestR1] );
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printf("R2=%g\n", E[bestR2] );
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printf("U2=%g\n", bestVoltage );
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81
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82
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return 0;
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83
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}
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